So, y must be positive since it is above the x-axis. This is possible.

In Roman numeral II, if (x, −y) is in the third quadrant, then x = negative, and −y = negative. This is only true if x = negative and y = positive. This could be true.

In Roman numeral III, if a point lies on the x-axis, then its value is 0, that would make the product of x and y zero, which contradicts the given information. Only the first two Roman numerals are possible given the constraints of the problem.

In Roman numeral I, if (−x, y) lies above the x-axis and to the right of the y-axis (that is, in the first quadrant), then x must equal a negative number, since all x-values to the right of the y-axis are positive, and the only way −x = positive is if x = negative. So, y must be positive since it is above the x-axis. This is possible.

In Roman numeral II, if (x, −y) is in the third quadrant, then x = negative, and −y = negative.

Alternatively, notice that we multiplied the number of each drink by the number of hours that drink was sold, then we added the two totals together: 6X + 7Y. This matches the expression in answer choice (D).

Convert the word problem into an expression representing the total coffees sold:

This solution can be verified by testing values. Let’s say X = 2 and Y = 3. If 2 lattes were sold each hour for 6 hours, then 2 x 6 = 12 lattes total were sold. If 3 americanos were sold each hour for 7 hours, then 3 x 7 = 21 americanos were sold.

*x*+

*y*, so:

*x* + *y* =

(6) + (1) = 7

Question 7 of 20

If Eric was 22 years old *x* years ago and Shelley will be 24 years old in *y* years, what was the average of their ages 4 years ago?

To do this problem, choose values for x and y. If you are choosing numbers, try to use low numbers that are easy to work with (such as 2, 3, 4, etc.).

Let’s say *x* = 2. If Eric was 22 years old 2 years ago, then today he is 24 years old. Four years ago, he would have been 20.

Let’s say *y* = 3.

The mathematics section of the SAT test consists of two 25 minute sections and one 20 minute section. The test questions in this section are either multiple choice or student produced response (grid-in) questions. Subjects tested in this section include number and operations, algebra and functions, geometry, statistics, probability, and data analysis. The writing section of the SAT test contains a 35 minute multiple choice section and a 25 minute essay section. The multiple choice questions test grammar, usage, and word choice through improving sentences, paragraphs, and the identification of sentence errors. The essay question deals with the development of a point of view on an issue.

Point B lies on YZ and Point C lies on XZ. BZ is congruent to CZ, and angle XYZ = 90. XZ – CZ = XA. What is the value of angle ACB? This is a Geometry question, so you’ll want to begin by drawing the figure on your own and filling in the given information. Let’s call angle ACB “z” to keep track of it.

We know a, z, and b are supplementary, so *a* + *b* + *z* = 180. We also know that (180 − 2*b*) + (180 − 2*a*) = 90, this is because the angle at X and the angle at Z must combine with the angle Y to make the sum of the interior angles of a triangle: 180°. Simplifying this second equation:

360 − 2*b* − 2*a* = 90.

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